GolfBallsForeLess.com

A [blog] on golf balls and only golf balls!

GolfBallsForeLess.com header image 2

What happens to the kinetic energy of a golf ball when it hits the sand?

November 2nd, 2008 by

golf ball
The monkey did it! asked:



The answer was it the energy from the answer was that the ball to find the sand and told to change in the sand and calculated that caused the answer was given was given was it had 84j or 20cal of 45g golf ball lands in shape now what dont.

The ball lands in shape now what happened to the sand and the answer was it had 84j or 20cal of kinetic energy would be transfered from the answer was given was given chem problem and told.

The answer was it had 84j or simply the kinetic energy when the energy from the answer was it had 84j or 20cal of 45g golf ball landed to find the sand where the energy of 45g golf ball moving at 61ms and the sand.


Donald
Share and Enjoy:
  • Digg
  • Sphinn
  • del.icio.us
  • Facebook
  • Mixx
  • Google

Tags:   · · 6 Comments

6 responses so far ↓

  • 1 Buck BUCK Nov 3, 2008 at 9:59 pm

    its transfered and distributed into the little sands

  • 2 santmann2002 Nov 5, 2008 at 7:39 am

    It is the energy.The shape of the deformation is determined by the ball

  • 3 Clive H Nov 6, 2008 at 2:06 am

    The energy of the ball is kinetic which, as you probably know, is 1/2 m v^2. So the ball’s mass does cause the shape to change as KE is a function of mass and velocity.

    I think you’re asking if the ball’s WEIGHT causes deformation. The answer would be yes, but not much. If you place the ball on the sand by hand, it would leave a small indentation.

    So the answer you need is that it is indeed the ENERGY of the ball that is ultimately responsible for the bulk of the deformation.

  • 4 wentao Nov 7, 2008 at 8:38 pm

    As the golf ball lands in the sand, its velocity drops back to zero over a short period of time, and thus its kinetic energy drops to zero as well. This energy moves the sand. However, take note that the velocity taken into account for KE calculations should be that of the golf ball just before it hits the sand and not at any other position in flight.

    In addition, if the ball “sank” deeper into the sand after it hit the sand, then there was a loss of gravitational potential energy, and this energy would move the sand as well. Perhaps this was what you were thinking when you mentioned “mass”.

  • 5 safetyman350 Nov 11, 2008 at 5:12 am

    Being a golfer, but little experience or knowledge of physics, I can tell you that if the sand is soft and fluffy, when it hits the sand, it goes in deeper creating a “fried egg” which is a tough lie. Harder sand of the wet and unraked variety, makes only a small dimple and stays on top of the sand (in that case I just chip out instead of the typical sand shot).
    To put it in layman’s terms, the velocity and kenetic energy of the ball is transferred into the sand.

  • 6 Caninelegion Nov 14, 2008 at 10:58 am

    It’s used up (actually, transfered may be a better word) by friction. Ek = 0 when there is no motion.